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Solve { (3x^2 - 12x -4) / (x^2-4x+9) } > 0.

I know the answer, but, i do not understand some steps.

Thank you for your co-operation.

2006-11-18 14:05:08 · 2 answers · asked by free aung san su kyi forthwith 2 in Science & Mathematics Mathematics

2 answers

You need to find where the numerator and denominator equal zero.
Set 3x^2 - 12x - 4 = 0, and solve for x.
Do the same thing for x^2 -4x + 9 = 0
These will be your critical values. You will have a total of 4.
Set up intervals. There will be 1 more interval than critical values, so there will be 4+1 = 5 intervals.
Test a point in each interval to see which intervals are positive. The positive intervals will be your answer.

2006-11-18 15:20:05 · answer #1 · answered by MsMath 7 · 1 1

Oh.... I thought this was a question about racism! LOL

But since I'm here... Remember PEMDAS.

You do what is in each parenthesis first.

Then do the exponents.

Then multiply and divide.

Then add and subtract.

As for setting it as > 0 for an inequality, I'm not that sharp.

Best Wishes,

Sue

2006-11-18 22:14:00 · answer #2 · answered by newbiegranny 5 · 1 0

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