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A sample of COCl2(g) in a reaction vessel at an initial concentration of 0.500 M is heated to 800°C. The equilibrium concentration of CO(g) was found to be 0.046 M. What is the equilibrium constant for the reaction at 800°C?

A. 0.00047
B. 0.0047
C. 0.047
D.0.00094

2006-11-18 12:54:16 · 4 answers · asked by Ashley C 1 in Science & Mathematics Chemistry

4 answers

For reaction aA <--> bB + cC, the Eq.constant K is defined as

K = (B^b * C^c) / A^a

Since in your equation a=b=c=1, and concentration for B=C, the equation simplifies to

K = B^2 / A

with B=0.046 and A=0.454 (0.454=0.500-0.046)

so K = 0.046^2 / 0.454 = 0.0047

2006-11-18 13:38:21 · answer #1 · answered by philly_wl 2 · 0 0

I could be making a mistake but the answer that I get is not on here. you would write the full reaction and make sure that the reaction is balanced. Then you ICE....which means initial, change and equalibrium. The initial concentration of .5 goes under the I column and the equilibrium concentration of CO goes under the E column. Do the math.

K eq = prdocuts/ reactants

2006-11-18 13:22:19 · answer #2 · answered by sophi p 2 · 0 0

I'll answer yours if you answer mine.
How much C4 can i pack up a bulls butt, to blow it's horns off, without making it's eyes water?

I am an explosives tech, so i didn't pull this one out of my a$$.

2006-11-18 12:58:30 · answer #3 · answered by AEracer40 3 · 1 0

E. Cancer

2006-11-18 12:56:35 · answer #4 · answered by Jerk my flergan! 1 · 0 0

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