can any one solve this problem?

Question

3x^2+9x+6

Answer 1

Factor out the 3:
3(x^2+3x+2)
Unfoil:
3(x+1)(x+2)
Take the roots:
x=-1 or -2

Answer 2

This is a classic case of having trouble factorising quadratic polynomials. People have had problems with this in the past. Maybe you should see 'similar questions' before wasting 5 points. Anyway, here's the answer:
3x^2+9x+6
The easieast way to factorise this is to split the middle term, that is '9x' into two terms. In order to get the two apprpriate terms needed, follow these steps:
1. Multiply the coefficient of the first term with the last term. (3*6 = 18)
2. Factorise the product (18)
18 = 1*18
2*9
3*6
3. Pick out two factors that add up to make the coefficient of the middle term. (3 + 6 = 9)
4.Split the middle term (9x = 6x + 3x)

Now let's get on with the factorisation:
3x^2+9x+6 = 3x^2 + 6x + 3x + 6
= 3x(x + 2) + 3(x + 2)
= (3x + 3)(x + 2)

Answer 3

I assume you mean factor, you didn't say
3x^2+9x+6
3(x^2+3x+2)
3(x+2)(x+1)

Answer 4

I'm assuming it's = 0 but even if it isn't the factorization is still correct.
3(x^2 + 3x +2) = 0
3(x+1)(x+2)=0
thus x = -1 or x = -2

Answer 5

3x^+2+9x+6
Group like terms, we get
3x^+9x+2+6
9x+9x+2+6
Adding like term, we get
18x+8
ans = 18x+8

Answer 6

90

Answer 7

One can but I think it may be assigned to you. So the question is ' can you solve this problem.'

Answer 8

what am i supposed to solve for? thats just a function

Answer 9

My dad said the first x shouldn't be there.