help with math problem?

Question

i hope i wrote this with no confusion, how do i simplify
(1/3+1/3x)/(1/x+1/3)

explanation is appreciated, thanks!!!

Answer 1

(1/3+1/3x)/(1/x+1/3)
Numerator = 1/3+1/3x
= x/3x + 1/3x = (x + 1)/3x

Denominator = 1/x+1/3
= 3/3x + x/3x
= (x + 3)/3x

Therefore numerator / denominator
= [(x + 1)/3x]/[(x + 3)/3x]
= [(x + 1)/3x] * [3x/(x + 3)]
= (x + 1)/(x + 3)

Answer 2

Use FOIL i.e. First Terms, Outer terms, Inner Terms, Last Terms. Multiply the corresponding terms together and add. List terms in order of highest exponents. I prefer using fractions myself but when doing problems here, I find that using decimals is less cumbersome.

.33*1/x=1/3x
.33*.33=.111
1/3x*1/x=1/3x^2
1/3x*1/3=1/9x
____________
1/3x^2+4/9x+.111
.111=1/9
1/3x^2+4/9x+1/9

Hope this helps.

Answer 3

Let's get everything inside the parens over common denominators first:

(1/3 + 1/3x) = (x/3x + 1/3x) = (x+1) / 3x

(1/x + 1/3) = (3/3x + x/3x) = (3+x) / 3x

Now we can put these over each other and see what happens:

(x+1) / 3x
-------------- =
(3+x) / 3x

(x+1) / (3+x)

Hope that helps!

~ ♥ ~

Answer 4

use foil

inside inside, inside outside, outside inside, outside outside

so 1/3 * 1/x + 1/3 * 1/3 + 1/3x * 1/x + 1/3x * 1/3

Answer 5

(1/3 - 1/3 + 1/3x) / (1/3 - 1/3 + 1/x) = 1/3x / 1/x
\\subtract 1/3 from each

1/3x * 3 / 1/x * 3 = 3/3x / 3/x
\\multiply each by 3

(3/3x * 3x/1) / (3/x * 3x/1) = (9x / 3x) / (9x / x)
\\multiply each by 3x over 1

(9/x / 3x) / (9x/x) = (9/3) / (9/1) = 3/9 = 1/3

Answer 6

(1/3+1/3x)/(1/x+1/3)

Remember BODMAS (Brackets Over Division Multiplication Addition Subtraction).

First work out the answer to 1/3. (0.33333333etc.)

0.3/0.3x/1/x+0.3

I'm presuming 1/3x means 0.3 times x?

Good luck.

Answer 7

(1/3+1/3x)/(1/x+1/3) = [(x + 1)/3x]/[(3 + x)/3x]
= [(x + 1)/3x]*[3x/(3+x)]
= (x+1)/(3+x)

Answer 8

blueeeeeeeeeee,
i told u before
it is
(x/3x+1/3x)/(3/3x+x/3x)=
=(x+1)/(x+3)

Answer 9

follow order tionsof opera

Answer 10

ask a teacher, go to ask.com or google