Compute the acceleration of a block sliding down a 30 degree incline, the coefficient of sliding friction being 0.20
...Thanks
2006-11-18 10:15:31 · 3 answers · asked by knicksfan000 1 in Science & Mathematics ➔ Physics
What is the answer with proper units???
2006-11-18 10:22:42 · update #1
What is the actual answer?
2006-11-18 10:27:01 · update #2
The force pulling the block down is m*g*sin(ø); the force of friction is k*m*g*cos(ø), The net force is the m*g*sin(ø) - k*m*g*cos(ø). The resulting acceleration is this force divided by m, so
a = g*sin(ø) - k*g*cos(ø)
a = g[sin(ø) - k*cos(ø)]
2006-11-18 10:21:30 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
you need to create a free body diagram. just draw a block on an inclined plane of 30deg. then add all of your forces. there will be a friction force that acts up the plane, a normal force that pushes up on the block perpendicular to the plane, weight of the block that acts straight down. any other forces that the problem statement specifies.
do the sum of the forces in the x and y directions. in x direction you should get: N(.2)-mgsin(30)=mass*acceleration
in y direction: N-mgcos(30)=0
solveing for N you get N=mgcos(30)
now plug in value of N into x-direction and you get acceleration =(1/m)*(.2mgcos(30)-mgsin(30))
there you have it. just plug in the values for gravity and mass of the block and you'll have the answer
2006-11-18 18:22:53 · answer #2 · answered by mosesisback19 1 · 0⤊ 0⤋
If you cannot simply plug in numbers...I suggest you drop whatever class you got this question in.
2006-11-18 22:23:58 · answer #3 · answered by adklsjfklsdj 6 · 1⤊ 1⤋