In the mathematical example of "24 + 23 + 22 + 21 + 20 + 19 = 129", how would I make a math formula that calculates this for me where "x" is the number of iterations (in this case 6 iterations) I want to arrive at an answer. For example, "24x" (where "x" is the formula), I would get back an answer of 129.
Thanks!
Jamie
2006-11-18 09:01:23 · 6 answers · asked by samea76 2 in Science & Mathematics ➔ Mathematics
Ooops... probably I didn't make my question clear enough. I would like to be able to "plug in" the number of iterations. For instance, where "x" is the number of iterations, here are some examples:
24 + 23 + 22 = 69
So I know my starting number (24) and I know how many iterations I want (3), but I need to know the answer (69).
Another example:
24 + 23 + 22 + 21 = 90
So I know my starting number (24) and I know how many iterations I want (4), but I need to know the answer (90).
How do I make a formula out of this where I can just "plug in" a number of iterations like this to get my answer?
Thanks,
Jamie
2006-11-18 09:09:50 · update #1
u can do it by
(n/2)(a+l)
where
n is no. of terms
a is first term
l is last term
2006-11-18 09:06:56 · answer #1 · answered by Dupinder jeet kaur k 2 · 1⤊ 0⤋
You need to be more specific. I believe this would work:
24x -15 =129
as 24 is the original number.
That would work for your equation only no other ones. I believe that is what you are asking, sorry if I misunderstood.
2006-11-18 17:06:40 · answer #2 · answered by Ted 2 · 0⤊ 0⤋
x= (+19)*3
I mean (24+19)*3=129
2006-11-18 17:06:57 · answer #3 · answered by a b 1 · 0⤊ 0⤋
For the equation you have drawn up the answer is x = 5.375
2006-11-18 17:05:28 · answer #4 · answered by Jet 6 · 1⤊ 0⤋
x=5.375
2006-11-18 22:24:52 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x-5.375
2006-11-18 17:46:03 · answer #6 · answered by xxd3bbst3Rsxx 2 · 0⤊ 0⤋