2006-11-18 07:02:05 · 5 answers · asked by rck_figo 1 in Science & Mathematics ➔ Physics
When an object is immersed partially or fully in a fluid it experiences an upward force that is equal to the weight of the fluid displaced.
2006-11-18 07:06:03 · answer #1 · answered by dj raz 1 · 0⤊ 0⤋
Archimedes Principle...hmmm. lemme see
Say that you have a full container or water. THen you placed a rubber ducky in there. Water would be displaced or in other words fall out of the container becuase of the object right? Well the weight of the water that falls out, and the wieght of the rubber ducky is going to be the same.
This is an easy and basic answer to how the Archimedes Principle works.
Hoped that helped
2006-11-18 07:14:52 · answer #2 · answered by Nobody Nobody but kyu 2 · 0⤊ 0⤋
Archimedes principle says: body submerged in a water weights less for the amount of exported water. For example if 1 dm^3 of gold weights 5 kg submerged into a water will weight 4 kg that is 5 kg - the gold volume (1 dm^3) of exported water that is 1 kg.
2006-11-18 08:22:19 · answer #3 · answered by fernando_007 6 · 0⤊ 0⤋
An object immersed in a fluid suffers an apparent weight loss, which equals weight of fluid displaced by the object.[Equals upward thrust of fluid]
2006-11-18 07:08:00 · answer #4 · answered by openpsychy 6 · 0⤊ 0⤋
If you weigh something in water, it weighs less than it did when weighed in air.
The apparent loss of weight of the object is equal to the eight of the water displaced
2006-11-18 07:26:10 · answer #5 · answered by rosie recipe 7 · 0⤊ 0⤋