Bob
2006-11-18 05:25:38 · 12 answers · asked by your pete 4 in Family & Relationships ➔ Friends
your pete bob?
2006-11-18 05:31:22 · answer #1 · answered by herbal ashtray 4 · 0⤊ 0⤋
nicely, you may desire to talk to her and notice what she needs in all this. yet she's have been given to be truthful with herself in all of this, if that is in undemanding terms her desiring a boyfriend then she desires to be attentive to whether that's the boy for her, or whether it fairly is that she likes him then she desires to easily be herself approximately it, and not get too previous to herself, and if he's began ignoring her it may desire to be that he only does not be attentive to a thank you to act round her now that they have kissed as a results of fact he's shy, or perchance in the experience that your pal has been organic putting herself available she's scared him off. on the top of the day it may desire to have only been a kiss and not something greater to it.
2016-12-30 14:53:36 · answer #2 · answered by Anonymous · 0⤊ 0⤋
bob man, she has blown you out for your long lost brother, Bobbob.
Suggest you take her little sister out (but have her back by 8).
2006-11-18 05:29:56 · answer #3 · answered by Matt 4 · 0⤊ 0⤋
Eff off and take lydia and bob with you, you point-gaming scumbag.
2006-11-18 05:39:24 · answer #4 · answered by mcfifi 6 · 0⤊ 1⤋
oh so your bob. yea sure why not. what did she do 2 u
2006-11-18 05:28:56 · answer #5 · answered by ♥ F@$H!0N ♥ 5 · 0⤊ 0⤋
maybe.... love the way you spelt lidia!!
no this is not bob..this is pete...dont even know him!!ha ha
2006-11-18 05:28:06 · answer #6 · answered by Lydia K 4 · 0⤊ 1⤋
but my name's bob short for kate. and we're lydias friends so you cant be!
2006-11-18 08:09:07 · answer #7 · answered by abbie g 2 · 0⤊ 0⤋
yes of course
2006-11-18 05:28:31 · answer #8 · answered by I love dooneys 6 · 0⤊ 0⤋
yeah i do not see any reson for u to break up
2006-11-18 08:00:17 · answer #9 · answered by Anonymous · 0⤊ 0⤋
Why not
2006-11-18 05:30:27 · answer #10 · answered by Anonymous · 0⤊ 0⤋