x= the square root of y+x divided by 5= what?
for y=25
2006-11-18 03:28:28 · 5 answers · asked by Ian H 2 in Science & Mathematics ➔ Mathematics
x= 5/4 or x= -5/4 if
x=(25^1/2 +x)/5, 5x=25^1/2+x, 4x=+ or - 5, x=+ or - 5/4
x= 6 1/4 or x= -6 1/4 if
x=25^1/2 + x/5, 4/5x=+ or - 5, x=+ or - 25/4
2006-11-18 03:38:27 · answer #1 · answered by merviedz trespassers 3 · 0⤊ 0⤋
x= the square root(y+x) / 5
=>5x= the square root(y+x)
=>(5x)^2= y+x
=>(5x)^2 - x - y = 0
=>25 x^2 - x - 25 = 0
=>x= (1/50)+(1/50)*(2501)^(1/2)
or x= (1/50)-(1/50)*(2501)^(1/2)
If you mean
x= the square root[(y+x) / 5]
=>(x)^2= (y+x)/5
=>5(x)^2 - x - y = 0
=>5 x^2 - x - 25 = 0
=>x=(1/10)+(1/10)*(501)^(1/2)
or x= (1/10)-(1/10)*(501)^(1/2)
2006-11-18 13:19:35 · answer #2 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
the square root of x, divided by 5, plus 1
square root=#
x=#x /5 +1
-1=-x+#x /5
-5=-x+#x
#x=-x-5
2006-11-18 11:40:34 · answer #3 · answered by Bill E. Bob 1 · 0⤊ 0⤋
x=(y+x/5)^1/2
x^2=25+x/2
5x^2- x = 25
x = 2.339
2006-11-18 11:53:02 · answer #4 · answered by manofnight12 2 · 0⤊ 0⤋
x=o
2006-11-18 11:37:20 · answer #5 · answered by lavender tots 4 · 0⤊ 0⤋