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A 115 kg solid gold statue is being raised from a sunken treasure ship.

2006-11-18 02:45:20 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

The density of gold is 19.3*10^3 kg/m^3. So to calculate the statue's volume
115 kg * (1 m^3/19.3*10^3 kg) = .00596 m^3. That mass of that volume of water
.00596 m^3 * (1 kg/1*10^3 m^3) = 5.96 kg.

The weight of the statue: 115 kg*9.8 m/s^2 = 1127 Newtons
The weight of the 5.96 kg water: 5.96 kg*9.8 m/s^2 = 58.4 Newtons. This is the amount of bouyancy provided by the water.

So the tension in the cable while the statue is still under water is 1127 - 58.4 Newtons =1069 Newtons.
After the statue is out of the water, tension is 1127 Newtons.

2006-11-18 10:22:02 · answer #1 · answered by sojsail 7 · 0 0

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