(a^2 + b)(b^2+a)
Multiply and
Verify your answer for a= -1,b= -2
2006-11-17 22:03:38 · 10 answers · asked by Dark angel 1 in Science & Mathematics ➔ Mathematics
a^2+b)(b^2+a)
L.H.S=a^2b^2+a^3+b^3+ab
=4-1-8+2=-3
R.H.S=(a^2+b)(b^2+a)
=(1-2)(4-1)
=-3
2006-11-18 01:36:16 · answer #1 · answered by Chucky 2 · 0⤊ 0⤋
(a^2 + b)*(b^2+a)=
a²b²+a³+b³+ab=
for a= -1,b= -2:
(-1)²(-2)²+(-1)³+(-2)³+(-1)(-2)
(1*4)+(-1)+(-8)+2=
4-1-8+2=
= -3 <<<<<<<<<<<<<<<<<<<<<<
proof:
(-1²-2)(-2²-1)=
(1-2)(4-1)=
-1*3=-3
₢
2006-11-18 07:13:41 · answer #2 · answered by Luiz S 7 · 0⤊ 0⤋
Simply arithmetics, no binomials needed:
= (-1*-1+(-2))(-2*-2+(-1)) = (1-2)(4-1) = -1(3)= -3
2006-11-18 06:27:35 · answer #3 · answered by hb9tza/qrp 1 · 0⤊ 0⤋
Q. (a^2+b)(b^2+a)
Ans.
(a^2)(b^2)+a^3+b^3+a*b
put a=-1 and b=-2
((-1)^2)((-2)^2)+(-1)^3+(-2)^3+(-1)(-2)
=> 1*4+(-1)+(-8)+2
=>the answer is -3
2006-11-18 06:31:58 · answer #4 · answered by Anonymous · 0⤊ 0⤋
a^2.b^2+a^3+b^3+ab
(ab)^2+a^3+b^3+ab
(-1.-2)^2+(-1)+(-8)+2
4-1-8+2
3-6
-3 (solved)
2006-11-18 06:14:25 · answer #5 · answered by fii 3 · 0⤊ 0⤋
(a² + b)(b² + a)
[(- 1)² +( - 2)][(- 2)² + (-1)]
[1 - 2][4 - 1]
[-1][3]
- 3
The answer is - 3
- - - - - - - - - - -s-
2006-11-18 10:49:45 · answer #6 · answered by SAMUEL D 7 · 0⤊ 0⤋
(a^2+b)(b^2+a)
=a^2b^2+a^3+b^3+ab
=4-1-8+2=-3
(a^2+b)(b^2+a)
=(1-2)(4-1)
=-3
2006-11-18 06:09:25 · answer #7 · answered by raj 7 · 0⤊ 0⤋
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2006-11-18 06:13:51 · answer #8 · answered by graham b 1 · 0⤊ 1⤋
ask ur maths teacher dear not here
2006-11-18 06:07:55 · answer #9 · answered by rick hei 2 · 0⤊ 1⤋
*yawn*
maths is boring
2006-11-18 07:25:06 · answer #10 · answered by Anonymous · 0⤊ 0⤋