I messed up on my last question. Once again working with logs and e.
2006-11-17 18:38:37 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
log 6^(2x)= log 9037984
2x*log 6= log 9037984
2x= log 9037984/log 6
x= log 9037984/(2*log 6)
x= log 9037984/log 6²
x= log 9037984 / log 36
₢
2006-11-18 00:08:58 · answer #1 · answered by Luiz S 7 · 0⤊ 0⤋
Log 9037984 / Log 6
Divide your answer by two and disco!
2006-11-17 18:40:28 · answer #2 · answered by alwaysmoose 7 · 0⤊ 0⤋
log (a^b) = b * (log (a))
using this logic, you can:
log [6^(2x)] = log 9037984
(2x) * log 6 = log 9037984
2x = (log 9037984) / (log 6) = 8.94
x = 8.94/2 = 4.47
2006-11-17 18:55:19 · answer #3 · answered by orca1006 2 · 0⤊ 0⤋
6^2x = 9037984
Take the ln (or simply logarithm to any other base) of both sides
ln (6^2x) = ln (9037984)
Simplify
2x ln 6 = ln 9037984
Therefore,
x = ln 9037984/2 ln 6
That's all!
^_^
2006-11-17 23:20:15 · answer #4 · answered by kevin! 5 · 0⤊ 0⤋
(2x)ln6 =9037984
x= 9037984/2ln6
x=9037984/ln(6^2)
x=9037984/ln36
i think with dis u can get d ans . i don't really have a calculator with me right now.
hope thhis helps you.
2006-11-17 21:11:57 · answer #5 · answered by tomzy 2 · 0⤊ 0⤋