were are using logs and e
2006-11-17 18:18:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2xlog10=log9037980
2x=6.9561
x=6.9561/2
=3.4781
2006-11-17 18:30:14 · answer #1 · answered by raj 7 · 1⤊ 0⤋
Take the log (base 10) of both sides of the equation:
log (10^2x) = log(9037980)
Bring the exponent out in front:
2x * log(10) = log(9037980)
But log(10) is one, so you have:
2x = log(9037980)
2x â 6.95607138
x â 6.95607138 / 2
x â 3.478
2006-11-18 02:54:59 · answer #2 · answered by Puzzling 7 · 0⤊ 0⤋
use log base 10
2x log 10 = log 9037980
2x = 6.956071...
2x = 6.96
x= 3.48
hope this helps
2006-11-18 03:55:41 · answer #3 · answered by fii 3 · 0⤊ 0⤋
2x log10 = log(9037980)
2x = log(9037980)/1 => x=log(9037980)/2
x=3.4781
2006-11-18 02:25:17 · answer #4 · answered by Anonymous · 1⤊ 0⤋