u hav 3 vertices of an equilateral triangle, How do u prove this with diagrams & calculations, using pi?

Question

This is for a maths assignement due, & i dont hav enough time 2 think about it all ( as i also hav 3 more different assignments due on top of that) so i just need a little help with it please...

This is for a maths assignement due, & i dont hav enough time 2 think about it all ( as i also hav 3 more different assignments due on top of that) so i just need a little help with it please...
What u r suposed 2 prove is why/how u hav 3 vertices of an equilateral triangle

Sorry im just so stressd umm here are the assignment directions: -cut a large circle out of a peice of paper. 1) fold the circle in half 2) now fold it in half again along the straight edge. You now have a right angle and have located the centre of the circle. 3) open out and fold one of the edge points onto the centre. You now have the 3 vertices of a large equilateral triangle. Prove this with diagrams & calculations, you will need Pythagoras' Theorum

Answer 1

what are you supposed to prove?

edit:
you mean why the three vertices of an equilateral triangle are concyclic? i am unable to make out theproblem

Answer 2

Connect the vertices. Inscribe a circle within the triangle. If the triangle is equilateral, the circle will meet each side at its midpoint.

It's not necessary to use pi, unless you want to measure the area of the circle or the triangle The area of the circle is pi*r^2.

To find the area of the triangle, drop a perpendicular from one of the vertices to the midpoint of the opposite side. Then multiply the altitude of the triangle by the length of its base, and divide by 2.

Answer 3

Can you please transpose the question as written in your assignment. What you are saying does not make much sense to me either. Triangle shave three vertices by definition. You can use pi to differentiate that one triangle is equilateral from another but you are not saying what you have to prove!

Answer 4

Your mentioning pi makes me wonder if you are using complex numbers, rotating the sides through 120 degrees using
cos(2pi/3) + i*sin(2pi/3)??

But as the previous answerer said, there isn't a specific enough question for us to answer!

Answer 5

suppose the vertices are (x1,y1), (x2,y2) and (x3,y3)

chk if |x2-x1|=|x3-x1|=|x3-x2|

and |y2-y1|=|y3-y1|=|y3-y1|
then its definitly a Euilateral triangle.


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