By 1999, the number of foreign-born residents of the United States had increased to about 25.8 million from 10.3 million in 1990. What percent increase is this from 1990?
2006-11-17 14:21:06 · 6 answers · asked by jamie d 2 in Science & Mathematics ➔ Mathematics
In millions, the 1st number is 10.3 and the 2nd number is 25.8.
Percentage increase = 100( 2nd - 1st ) / 1st = 100 (25.8 - 10.3) / 10.3
= 150.5
There was a 151% increase in the number of foreign-born residents of the United States between the years 1990 and 1999.
2006-11-17 14:24:27 · answer #1 · answered by Clueless 4 · 0⤊ 1⤋
Percent increase is the amount of the increase, divided by the original total, then multiplied by 100.
So subtract 25.8 - 10.3 to find the increase: 15.5
Divide by 10.3 : 1.504854...
Multiply by 100: 150.4854 % - round as desired
2006-11-17 14:27:25 · answer #2 · answered by hayharbr 7 · 0⤊ 0⤋
Are you willing to pay this math genius $100 an hour to help you? Math geniuses don't work for free you know. Even they need to make money and live.
2006-11-17 14:24:48 · answer #3 · answered by The Prince 6 · 0⤊ 0⤋
It increased by just over 150%.
2006-11-17 14:26:30 · answer #4 · answered by UncaSpike 1 · 0⤊ 0⤋
UPDATE: I originally said 250.49%, but after seeing the response from "Clueless", I can see that I was wrong. Clueless is right; go with his answer. Good job, Clueless.
2006-11-17 14:24:22 · answer #5 · answered by Daniel M99 2 · 0⤊ 0⤋
10.3/100=25.8/x
10.3x=2580
x=250.49
250.49%
2006-11-17 14:24:40 · answer #6 · answered by bourqueno77 4 · 0⤊ 0⤋