2006-11-17 13:31:40 · 4 answers · asked by Cf Precious 3 in Education & Reference ➔ Homework Help
Zero because the only way to get 11 is a 6 and a 5.
2006-11-17 13:37:12 · answer #1 · answered by hayharbr 7 · 0⤊ 0⤋
a truthful cube potential you have an equivalent probability of touchdown on the two component whilst rolled. There are thirty six complete possibilities through fact there are 6 on one die and 6 on the different so 6 * 6 = 36. To get 6 you will would desire to roll a million on the 1st die and 5 on the 2d or 5 on the 1st and a million on the 2d...or 2 on the 1st and four on the 2d or 4 on the 1st and a pair of on the 2d...or 3 on the 1st and 3 on the 2d...it is 5 there. Then to get 11: 5 on the 1st & 6 on the 2d or 6 on the 1st and 5 on the 2d, that's 2 extra for an entire of 7. subsequently the probability would be 7/36.
2016-12-10 11:05:23 · answer #2 · answered by ? 4 · 0⤊ 0⤋
I agree with the others because there isn't a double that equals 11 on a dice unless they make a dice that has 5.5 on it.
2006-11-17 13:44:45 · answer #3 · answered by Anonymous · 0⤊ 0⤋
0%. Last time I checked 5.5 was not one of the numbers on a die.
Or am I missing something in your question?
2006-11-17 13:35:15 · answer #4 · answered by troythom 4 · 0⤊ 0⤋