a slingshot consists of light leather cup containing a stone that is pulled back against two rubber bands. it takes a force of 30.0 N to stretch the rubber bands to 1.00 cm. what is the potential enger stored in the bands when a 50 g stone is placed in the cup and pulled back 20 cm from its equilibrium position? with what speed does the stone leave the slingshot?
2006-11-17 09:11:32 · 1 answers · asked by Amanda R 2 in Science & Mathematics ➔ Physics
dont just want the answer, need steps to solve it too...
2006-11-17 09:11:56 · update #1
answer is 60.0 J and 49.0m/s for each answer, can't figure out how though
2006-11-17 09:31:45 · update #2
Since the stone did not gain any potential energy, the energy is stored in the slingshot bands
=F*d
=30*.2
=6
Assume all of the energy gets transferred to the stone's kinetic energy in 20 cm
1/2 *m*v^2
set equal to potential and solve for v
=15.5 m/s
j
2006-11-17 09:18:23 · answer #1 · answered by odu83 7 · 0⤊ 0⤋