Algebra Math Question...Power Equations...Cant Figure it out?

Question

Solve following power equations and check solutions

(x+2)^2=5

(a+3)^2+5=2

Dude is completely wrong, if he checked the answers or knew how to do math he would have seen that.

Answer 1

First question:
Take the sq. root of both sides: x+2=+/-(sqrt5)
Then subtract 2:
x = -2 +/-(sqrt 5)

Second prob: subtract 5 first:

(a+2)^2 = -3
Take the square root of both sides: (a+2) = +/-(sqrt(-3)

sqrt (-3) = i*sqrt 3

a+2 = +/-(i*sqrt 3)

Then subtract 2: final answer: -2 +/-(i*sqrt3)

Answer 2

x = 5^(1/2) - 2

whatever that is as a fraction

a is not real. there is no square root of -3, unless you go complex, which the answer to a is ((3^(1/2))i) - 3

or a = -3 + ((3^(1/2))i) where i is the complex number (-1)^(1/2)

Answer 3

for the first one x=1 (1+2)^2=5

x=one

for the second one a= -12 (-12+3)^2+5=2

a=negative twelve

Answer 4

I used the definition of a logarithm. LOGaB = X (log with base a to B = x) is an identical as a^x = b (a raised to the x power = b) utilizing this to resolve for C: Q = rx^2c Q/r = x^2c (devide each and each and every aspect through r) then utilizing the def of logarithms: LOGx(Q/r) = 2c and deviding each and each and every aspect through 2 c = (a million/2)LOGx(Q/r) This definition continually tricks me. yet in this, matching the symbols of the definition I gave, x is the equivalent of a, (Q/r) is the equivalent of B and 2c is the equivalent of x.