solve. round th the nearest tenth if necessary.?

Question

tis year ,there are 960 scholarship accplicants , which is120% of the number of applicants last year. find the number of applicants?

Answer 1

Is this a trick question? The answer is there are 960 applicants this year...

If you mean how many were there *last* year, the answer is 800 applicants.

x * 120% = 960
x = 960 / (120/100)
x = 960 * (100/120)
x = 8 * 100
x = 800

Double-checking:
800 applicants last year
20% more = 160 applicants
Total this year = 960 applicants

Answer 2

Let x=the applicants of the previous year (I believe this is what you're looking for)

Then (120/100) * x = 960

x = 960* 100/120 =800

So they had 800 applicants last year

Answer 3

take 960/6 and then times by 5
so in an equation it is

(960/6)*5=last years
this works because if 960 is 120% then a sixth of that is 20% and times by 5 to get 100%

Answer 4

alright, seriously now - all of you middle schoolers need to start doing your own homework!!

960 is 120% of x (the number of applicants last year)
so, you need to set up your equation --> 960 = (120/100) * x
then, solve for x

Answer 5

You say there are 960 applicants and then ask the number of applicants.

One, that's gotta be messed up.

Two, this is a dumb question. The is pre-pre-pre algebra.

Answer 6

800

Answer 7

800

Answer 8

960 = x * 120/100
960 = 120x/100
96000 = 120x
96000 / 120 = x
800 = x

Answer 9

1.2x = 960
x = 960 / 1.2
x = 800

Answer 10

$4250=.17N I were given this equation by putting forward to myself $4250 is (=) 17% of(x) what decision (N). Then divide each and each and every area of the equation by .17 and also you get $25,000. you may examine your answer by multiplying $25,000 by 17% and also you get $4250.