Don't know which is strongest, but hot is fastest.
You can catch cold.
2006-11-17 06:49:08
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answer #1
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answered by Anonymous
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First and foremost, it's not possble to have water at a temperature of -100 oC, it would be ice!
What you are really asking involves something called heat capacity, Cp. This is a measure of how much energy a substance can absorb before changing temperature by 1 oC. Cp does not depend on temperature, only on the material. There is also something called an energy of phase change, which is the amount of energy it takes to go from solid to liquid, liquid to gas, gas to solid, or any other combination of states. This energy is MUCH greater than changing temperature within a phase.
So to answer your question as you put it, you would probably end up with a mixture of water and ice at 0oC. The hot water would have to warm the ice up to 0 oC, then try to melt it. There wouldn't be enough energy to melt it all, so you would get the mixture.
2006-11-17 06:49:54
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answer #2
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answered by Duluth06ChE 3
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This question isnt as simple as it appes to answer. At -100oC it would certainly not be water, but would be ice. Next... i am assuming that this volume of water is only just touching 100oC and by this i mean none of it has actually turned to steam. If some has turned to steam then it will lose some energy to the ice before it even turns back to water and will still be 100oC considering that taking s energy from 100oC steam will turn it to100oC water before the temperature starts to decrease.
But a simple model of this would result in a 0oC solution, which would probably be a mix of water and ice, since both exist at that particular temperature.
2006-11-17 07:26:36
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answer #3
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answered by Article 82 2
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Water that is below 0 C is ice (at normal pressure).
If you add energy to ice, the temperature will rise fairly linearly until you get to the phase transition. Then the rise in temp will slow until after the phase transition, after which the temp will rise more.
However, since your water is equally above and below that ice phase transition, it should equal out in the amount of energy to reach the mean, which is 0 C.
2006-11-17 06:51:00
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answer #4
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answered by nondescript 7
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They would both end up at room temperature. Heat energy is transferred from hotter to colder. The hot water would 'try' to give its heat to the cold water, which wouldn't accept enough to bring it up to room temperature. Any excess would transfer to the room.
2006-11-17 21:04:07
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answer #5
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answered by Older&Wiser 5
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properly in case you had a cup of water and you boiled it (making it warm) it may turn to steam and evaporate. in case you took that comparable cup properly worth of water and iced up it (making it chilly) you may desire to knock somebody out or perhaps kill them with an ice bite. I vote for chilly being the main efficient.
2016-12-29 04:11:14
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answer #6
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answered by ? 4
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-100 c and cold is the strongest
2006-11-18 06:19:01
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answer #7
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answered by Anonymous
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this is a simple logical answer. if you add 100 degrees centigrade water to -100 degrees centigrade water it will level out to 0 degrees centigrade!!!
2006-11-17 06:52:15
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answer #8
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answered by e1-ferrari 2
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warm water
2006-11-17 06:43:02
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answer #9
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answered by brenda4ever 6
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0c
2006-11-17 06:43:30
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answer #10
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answered by Dan A 2
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