Lea is 6 yrs. older than sue & jon is 5 yrs. older than lea and the ages add up to 41. how older is sue?

Answer 1

Sue's age = s
Lea = s + 6
John = 5 + (s + 6)

s + (s+6) + (5 + [s+6]) = 41
Since it's all addition you can basically remove the parenthesis:
s+ s + 6 + 5 + s + 6 = 41
Combine everything:
3s + 17 = 41
Subtract 17 from both sides:
3s = 24
Divide by 3 on both sides:
s = 8

Check it out by filling in the ages:
Sue = 8
Lea is 6 years older than Sue = 14
Jon is 5 years older than Lea = 19
8 + 14 + 19 = 41

Answer 2

Lea (L) = Sue (S) + 6
Jon (J) = Lea + 5
= (S+6)+5
= S + 11
Sum of ages, (S + J + L) = 41
i.e. S + (S+11) + (S+6) = 41
3S + 27 = 41
Solve this, and you will get the age of Sue as 8 years old.
Lea is 14 years old and Jon is 19 years old for the information.

Answer 3

let L = age of Lea, S = age of Sue, and J = age of Jon.
Lea is 6 yrs older than Sue so L=S+6
Jon is 5 yrs older than Lea so J=L+5
L+S+J=41.
we want to know S, so rewrite all ages in terms of S.
Since L=S+6, you can say that J=(S+6) + 5 or J=S+11.
That means you can say that
L+S+J=41 can be written as (S+6) + S + (S+11) = 41
Solve for S. 3S+17=41.
3S=24.
S=8.
So Sue is 8 yrs old, Lea is 14, and Jon is 19.

Answer 4

Lea= Sue +6
Jon= Lea+5
Lea+Sue+Jon=41

L=s+6
j=(s+6)+5
s+6 +s+(s+11)=41
3s+17=41
-17 -17
3s=24
s=8
L=14
j=19

Answer 5

Let Sue's age equal x
Let Lea's age equal x + 6
Let Jon's age equal (x + 6) + 5 = x + 11

x + x + 6 + x + 11 = 41
3x + 17 = 41 (Subtract 17 from both sides)
3x = 24 (Divide both sides by 3)
x = 8

Sue's age = 8
Lea's age = 8 + 6 = 14
Jon's age 8 + 6 + 5 = 19
QED

Answer 6

Let Lea = x
Sue = y
Jon = z
We can draw up three equations using the given data. They are:
x = y + 6.....Eq 1.
z = x + 5.....Eq 2.
x + y + z = 41.....Eq 3.
Consider Eq 1
x = y + 6
y + 6 = x
y = x - 6
Now work with Eq 3
x + y + z = 41
x + (x - 6) + z = 41 (From the working of Eq 1)
x + (x - 6) + (x + 5) = 41 (From Eq 2)
x + x - 6 + x + 5 = 41
3x - 1 = 41
3x = 41 + 1
3x = 42
x = 42/3
x = 14
Now substitute the value of 'x' in Eq 2
z = x + 5
z = 14 + 5
z = 19
Substitute the value of 'x' in Eq 1
x = y + 6
14 = y + 6
14-6 = y
8 = y
y = 8

x = 14, y = 8 and z = 19
Sue = y
Sue is 8 years old

Answer 7

L = S + 6
J = L + 5
J + L + S = 41

J = Jon's age
S = Sue's age
L = lea's age

Solve the system of equations... there are 3 unknowns and 3 equations... substitution should be used.

Answer 8

L=6+S
J=5+L
L+J=11+S+L
L+S+J=41
S=30-S-L
L=30-2S
30-2S=6+S
3S=24
S=8
L=14
J=19

Answer 9

8 yrs old , next time do your own homework.
gabe