according to the following chemical reaction:?

Question

AI2O3 (s) + C (s) --- AI (s) + CO2 (g). How many grams of carbon are required to produce 1.00g of aluminum, and what is the coefficient in front of CO2.

Answer 1

OK, first we have to balance the equation. We've got a compound with 3 O's on the right and one with 2 O's on the left, so first let's get them equal: 2Al2O3 + C --> Al + 3CO2. Now, the C and Al can be used to balance the rest out: 2Al2O3 + 3C --> 2Al + 3CO2. That answers your second question (3), and we'll need it for the first too.

Now, we need to figure out how many moles of aluminum are in a gram. The moloar mass of aluminum is 26.98, so there are 26.98 grams in a mole. There are therefore 1/26.98 moles in a gram.

Now, we can see from the balanced equation that it takes 3 moles of carbon to make 2 moles of aluminum. So you will need (3/2)/26.98 moles of carbon. The molar mass of carbon is 12.01, so you need (3/2)*12.01/26.98 grams of carbon. Do the math and it works out to 0.67 grams of carbon. It makes sense that it should be less than a gram, since carbon's molar mass is less than half of aluminum's.

So your answers are: 0.67g, 3.

Answer 2

the coefficient in front the two AgCl and AgNO3 is "2" right this is the tactic for fixing the question (using ratio): BaCl2 : AgCl a million : 2 (those numbers are the coefficients) x : 0.635g (those are the a lot) x = (0.635 x a million) / 2 = 0.3175g

Answer 3

Are you looking for a handout? Get real and do this yourself.