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Question

The period of the earth around the sun is 1 year, and it is at a distance of 150 million kilometers from the sun. An asteroid in a circular orbit around the sun is at a distance of 632 million kilometers from the sun.

Already determined that the period, Ta, of the asteroid orbit in years is (632/150)^(1.5) * 1 year.

NEED TO DETERMINE the orbital velocity of the asteroid in m/s assuming 365 days in one year.

Answer 1

Calculate the number N of seconds in a year (365*24*60*6). Time t in s = N*Ta. Velocity in m/s = 2*pi*632,000,000*1000/t.

Answer 2

1. Use the third Kepler Law
2. Use the relation v = w * r