2006-11-17 02:52:36 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Xc=1/2π f C
As you can plainly see, capacitive reactance is a function of both capacitance and frequency.
If you work the arithmetic, you will see that the reactance decreases as capacitance increases while freqency remains stable, thus is inversely proportional.
You can work through the various permutations and chart the various relationships.
2006-11-17 03:03:10 · answer #1 · answered by credo quia est absurdum 7 · 0⤊ 0⤋
Capacitive reactance (X sub c) is equal to 1/(2pifC), where
pi = 3.1416 (approximately)
f = the frequency of the alternating current in cycles per second
C= capacitance in Farads.
As you can see, the greater the Capacitance, the less the reactance. Also, the greater the frequency, the less the reactance.
2006-11-17 03:11:11 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
The reactance of the capacitor, and for that reason its impedance, it is the equivalent of AC resistance, relies upon on frequency. So, with various frequency the blend of resistor and capacitor varieties a various skill divider.
2016-12-30 14:02:52 · answer #3 · answered by mccasland 3 · 0⤊ 0⤋
capacitive reactance=1/(2pifc)
where pi=3.142
f=frequency of signal
c=capacitance
it is inversely proportional to capacitance
2006-11-17 05:28:17 · answer #4 · answered by Anuj 3 · 0⤊ 0⤋
Xc = 1/(2 * pi * freq * C)
Xc is capacitive reactance.
freq is frequency in hertz.
C is capacitance in farads.
2006-11-17 03:00:54 · answer #5 · answered by Mark P 5 · 0⤊ 0⤋