2006-11-17 02:12:23 · 26 answers · asked by Anonymous in Entertainment & Music ➔ Movies
Man, all these people think Brad Pitt is so hot and sexy and I just don't see it. Anyway, Edward Norton is a much better actor by a long shot. He has done incredible work in all his roles, especially American History X. What a great movie.
2006-11-17 02:48:26 · answer #1 · answered by svg7373 3 · 1⤊ 0⤋
Edward Norton is much better at acting than Brad Pitt.
2006-11-17 08:30:18 · answer #2 · answered by LittleMiss 3 · 0⤊ 0⤋
Edward Norton.
He puts his heart and soul into every movie (think 'American History X,' & 'Primal Fear.' Although he's good looking, he's not known for the best looks like Brad Patt, which gets really annoying. Brad Pitt's looks almost takes away from his movies. Brad Pitt, in his movies, LOOKS like an actor. Edward Norton looks like a REAL normal person in his movies, and that's the idea, to forget you're watching an actor and to really feel like the plot is happening in real life.
2006-11-17 02:21:51 · answer #3 · answered by A 2 · 1⤊ 0⤋
2
2016-08-23 02:15:57 · answer #4 · answered by ? 3 · 0⤊ 0⤋
Brad Pitt
2006-11-17 02:19:56 · answer #5 · answered by Anonymous · 0⤊ 1⤋
Edward Norton
2006-11-17 02:19:19 · answer #6 · answered by Anonymous · 2⤊ 0⤋
Edward Norton
2006-11-17 02:19:14 · answer #7 · answered by jennaput 2 · 2⤊ 0⤋
Brad Pitt.
2006-11-17 02:39:34 · answer #8 · answered by Marisol C 1 · 0⤊ 0⤋
Edward Norton by a landslide,but he doesn't have the massive popularity that Brad Pitt has.
2006-11-17 02:17:27 · answer #9 · answered by Celebrity girl 7 · 2⤊ 0⤋
Brad Pitt is hot, no question. However, in terms of acting I think Ed Norton takes the cake. Look at Fight Club, the acting was outstanding! But that's not the only film he's also in Frida, American History X (which if you haven't seen it, PLEASE rent it), and even the recent film, The Illusionist, was only good because he was in it. So Brad Pitt - very hot, but Ed Norton very talented.
2006-11-17 02:22:25 · answer #10 · answered by Rayslittlegurl 3 · 2⤊ 0⤋