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Let a side of the square be 'x' and a side of the pentagon be 'y'.
First, is the pentagon a regular pentagon or a pentagon drawn at random? If it isn't regular, then the ratio is impossible to determine as each side of the pentagon can be different. So I'll assume that it's regular. In a regular pentagon, all the sides are equal.
Perimeter of square = 4x
Perimeter of regular pentagon = 5y
From question,
4x = 5y
4x/y = 5
4(x/y) = 5
x/y = 5/4
The ratio of a side of a square to that of a side of the pentagon is 5:4.
A side of the square must be larger than a side of the pentagon if the perimeters are equal.

2006-11-18 21:34:57 · answer #1 · answered by harshit_j1992 1 · 0 0

Let a side of the square be 'x' and a side of the pentagon be 'y'.
First, is the pentagon a regular pentagon or a pentagon drawn at random? If it isn't regular, then the ratio is impossible to determine as each side of the pentagon can be different. So I'll assume that it's regular. In a regular pentagon, all the sides are equal.
Perimeter of square = 4x
Perimeter of regular pentagon = 5y
From question,
4x = 5y
4x/y = 5
4(x/y) = 5
x/y = 5/4
The ratio of a side of a square to that of a side of the pentagon is 5:4.
A side of the square must be larger than a side of the pentagon if the perimeters are equal.

2006-11-18 14:10:29 · answer #2 · answered by Akilesh - Internet Undertaker 7 · 0 0

The same question came in today's Hindu Young World :)

To your question: The answer CANNOT BE FOUND. This is so because you have just stated "pentagon". Only if it is a regular pentagon can we find the ratio of the sides. If it is an irregular pentagon, then the sides of the pentagon will be different in length. So we cannot find the answer.

Assuming that you are referring to a regular pentagon, the answer is:

5: 4

Solution steps:

Let the perimeter be P.
Side of square: s
Side of Regular Pentagon: rp

Square has four sides. Pentagon has five sides.

4s = 5rp = P

4s = 5rp

thus, s / rp = 5 / 4

2006-11-17 00:43:56 · answer #3 · answered by Flashy V 2 · 0 0

4:5 = square:pentagon

4/5=square/pentagon

2006-11-17 04:53:24 · answer #4 · answered by Baku 2 · 0 0

Ratio of Square:Pentagon is 5:4

2006-11-17 00:43:04 · answer #5 · answered by Go CoOl 2 · 0 0

1 side of pentagon is 4 and square is 5
so 5:4

2006-11-17 00:42:25 · answer #6 · answered by ilovemydogii 4 · 0 0

assuming the polygons are regular,

let a be the side of square ,means perimeter=4a
let b be the side of pentagon,means perimeter=5b
so 4a=5b
a/b=5/4
so a:b=5:4

2006-11-17 01:17:55 · answer #7 · answered by Anonymous · 1 0

I think the ratio should be 4:5

2006-11-17 00:40:29 · answer #8 · answered by suchsi 5 · 0 1

very simple my dear as perimeter of square is 4a where a is side of squre , if b is side of pentagon 5b is perimeter of pentogon
as u said taking ratio of these two we get 1.25

2006-11-17 05:11:44 · answer #9 · answered by Rajeshwara chary S 1 · 0 0

perimeter of asquare=4*side1
perimeter of apentagon=5*side2

perimeter of square=perimeter of pentagon
4*side1=5*side2
side1:side2=5:4

2006-11-17 03:21:35 · answer #10 · answered by JACKREX 2 · 0 0

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