Three guys had a drink at my bar and i gave them a bill for $30.......
Each guy gave me $10.....
But I then realized the correct total was $25.........
Naughtily, I only reimbursed them $1 each so they had now paid a total of $27......
I kept the naughty $2..........My question is...if the drinks were $27, and I kept $2.00 that only adds up to $29 , so where did the other $1 go.......?
2006-11-16 22:36:13 · 14 answers · asked by dawn 3 in Science & Mathematics ➔ Mathematics
You have to bear in mind that the drinks were not actually $27 dollars, it was $25. Just because you gave them a dollar each back, they ASSUMED it was $27.
Even though they had paid $27, you still had to pay their bill of $25 which would leave you the $2.....
the missing $1, is therefore, not a missing dollar....!
2006-11-16 22:56:11 · answer #1 · answered by Crap_At_Maths 2 · 0⤊ 0⤋
In fact the guys spent only $ 27 in all - ie., $ 25 towards correct total of the Bill and naughty $ 2 being kept by you.
$ 25 (Drink) + $ 2 (Retained) = $ 30 (Paid) - $ 3 (Returned)
There is no other $1 to go any where ! Don't confuse /be confused.
2006-11-16 23:06:52 · answer #2 · answered by Alrahcam 4 · 0⤊ 0⤋
As you said the total was $30, each gave $10 which means they add up to $30. But after you realised the total was $25, you re-imbursed each $1 which means you have $27 at your hand.
But you didn't take $2 from them because, from the $10 each gave, you paid them back $3 which is equal to the naughty $2 you took and the missing $1.
Problem Solved
2006-11-16 23:11:17 · answer #3 · answered by Imtiyaz G 4 · 0⤊ 0⤋
You reimbursed them £1 each
as there are three men 3 x £1= £3
£25 + £3= £28
£30 - £28= £2 ( which you kept you sneak)
therefore all square except you over-charged for the drinks
2006-11-16 22:47:11 · answer #4 · answered by the_immortal89 2 · 0⤊ 0⤋
you wouldn't have the $2 dollars because if they paid $30 and were reimbursed $1 each. They only paid what the drinks cost i.e. $27.
Conversely if the drinks cost $27 and you kept $2 then you could only reimburse them with $1 rather than $3.
2006-11-16 23:46:54 · answer #5 · answered by spoon_bender001 2 · 0⤊ 0⤋
There was no missing buck. Your question was inconsistence.
From your assumption on the third line (the correct total was $25). Therefore, the drinks were not $27 as you made out on your fifth line, they were $25. So, the guys paid $27 & you kept $2.
=> There was no missing buck.
2006-11-17 00:00:09 · answer #6 · answered by ddntruong 2 · 0⤊ 0⤋
you are just playing with words
there is no missing buck
yo got $30 out of which you returned $3 in effect the guys paid $9 each and therefore $27 and you earned a profit of $2
$the $25 is just to confuse us
2006-11-17 01:17:31 · answer #7 · answered by oee22 2 · 0⤊ 0⤋
The drinks were not $27 they cost $25.
2006-11-16 23:17:48 · answer #8 · answered by Anonymous · 0⤊ 0⤋
they each paid you$10-$1returned
=$9 each=$27 in total
the bill came to $25 leaving you with
$2 for your sky-rocket-what's your
problem?
i hope that you don't want a tip as
well after 'skying' 66.67 cents
from each of the three guys
i am glad that i was not one of the
three guys that you conned
66 2/3 cents from
(3x66 2/3c=$2)
i hope that this helps
2006-11-17 00:09:00 · answer #9 · answered by Anonymous · 0⤊ 0⤋
you gave 3 guys $1 each so that takes the bill to $28.You took the last $2.There is no other $.
2006-11-16 22:45:43 · answer #10 · answered by kerrie h 3 · 1⤊ 0⤋