the volume of a right cylinder varies jointly w/ the square of its radius and its height. when the radius is 2cm and the height is 6cm , the volume is 2cm and the height is 6cm, the volume is 75.36 cm3
A.)what is the constant of variation?
B)what is the eq'n of variation?
C)what is the volume if r=3cm and h=5cm?
ANSWER USING JOINT VARIATION...
2006-11-16 21:10:49 · 4 answers · asked by FaLLen_sIrEn 1 in Science & Mathematics ➔ Mathematics
Your basic equation for volume is
V = Pi * R^2 * H (this is the answer to part B)
If you put the values for radius and hight into that equation you have
V = Pi * 4 * 6
We know Pi is 3.14159, so the equation solves
V = 75.39822369
I think you mistyped the 6 when aiming at the 9.
Your constant is Pi.
Putting the values for R=3 and H = 5 into that equation will get
V = Pi * 3^2 * 5
V = 3.14159 * 9 * 5
V = 141.372
2006-11-16 21:37:47 · answer #1 · answered by Trailcook 4 · 0⤊ 0⤋
A)let constant be x
then acc. to given condition
V=x*r^2*h
75.36 =x*2^2*6
75.36 =x*4*6
75.36 =x*24
x=75.36/24
x=3.14
B)so eq. becomes
V=3.14*r^2*h
C)V=3.14*3*5
2006-11-16 21:53:35 · answer #2 · answered by Dupinder jeet kaur k 2 · 0⤊ 0⤋
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2016-05-21 22:17:30 · answer #3 · answered by Ellen 3 · 0⤊ 0⤋
Trailcook is correct.
2006-11-16 22:19:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋