2+3(x - 4) < 3(2x - 5)
5(x - 4) < 3(2x - 5)
5x - 20 < 6x - 15
X < 5
2006-11-16 19:51:33 · 13 answers · asked by Miss LaStrange 5 in Science & Mathematics ➔ Mathematics
nope
2+3(x-4) < 3(2x-5)
2+3x-12 < 6x-15
3x-10 < 6x-15
-3x < -5
x < 5/3
2006-11-16 20:02:48 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Not unless the 2+3 is actually a factor (2+3), if not it should be,
2 + 3(x-4) < 3(2x - 5)
3x -10 < 6x -15
substracting 3x from both sides,
-10 < 3x -15
=> 3x > 5
then,
x > 5/3
2006-11-17 10:18:25 · answer #2 · answered by yasiru89 6 · 0⤊ 0⤋
No. this is not correct.The correct steps are as following
2+3(x - 4) < 3(2x - 5)
2+3x-12 < 3(2x - 5)
3x - 10 < 6x - 15
3x -6x < -15+10
-3x < -5
3x > 5 (When you multiply both sides of an inequality wuth -1, change the sign of inequality.)
x > (5/3) (this is final answer)
I hope this helpes you. All the best.
2006-11-17 04:22:54 · answer #3 · answered by Paritosh Vasava 3 · 0⤊ 0⤋
Wrong.
In a mathematic operation, one should peform the multiplication and division first before performing the addition and subtraction.
Hence, the inequality should be:
2 + 3(x-4) < 3(2x-5)
2 + 3x - 12 < 6x -15
3x -10 < 6x -15
15 - 10 < 6x - 3x
5 < 3x
x > 5/3
2006-11-17 04:05:12 · answer #4 · answered by orhhai 2 · 0⤊ 0⤋
No
2+3x-12<6x-15
3x-10<6x-15
3x-6x<-15+10
-3x<-5
x<5/3
2006-11-17 04:05:50 · answer #5 · answered by Princess 2 · 1⤊ 0⤋
2 + 3x - 12 < 6x -15
3x -10 < 6x -15
-3x < -5
x < 5/3
2006-11-17 04:04:57 · answer #6 · answered by Anonymous · 1⤊ 0⤋
no, it's incorrect. here's the correct answer:
2+3x-12 < 6x-15
3x-10 < 6x-15
5<3x or 3x>5
in the first step, 2+3(x-4), only the 3 gets distributed to the (x-4). once you distribute, THEN you put the 2 in front, ending up with 2+3x-12.
2006-11-17 03:59:40 · answer #7 · answered by christina rose 4 · 1⤊ 0⤋
No.
2 + 3x - 12 < 6x - 15
3x - 10 < 6x - 15
3x < 6x - 5
-3X < -5
3x < 5
x < 5/3
I think. I'm positive your answer is wrong. But I'm not sure if I'm right. Sorry!
2006-11-17 04:01:38 · answer #8 · answered by ThatLady 5 · 0⤊ 1⤋
2+3(x-4) < 3(2x-5)
2+3x-12 < 6x-15
-3x < -1
x > 1/3
I hope you can correct it
2006-11-17 04:04:22 · answer #9 · answered by MetZ 2 · 0⤊ 1⤋
no.
you must distribute the 3 first as opposed to adding the 2.
2006-11-17 03:56:41 · answer #10 · answered by James L 1 · 0⤊ 0⤋