Find the center, vertices, foci, and asymptotes.?

Question

Find the center, transverse axis, vertices, foci, and asymptotes.
x^2 - 9y^2 - 2x - 18y - 9 = 0

The center is at ( , ).

The coordinates of the two vertices are ( , ) and ( , ).

The coordinates of the two foci are ( , ) and ( , ).

The slope in the equation for the asymptotes.

Answer 1

I'll help set it up
but, honesty, it isn't that hard and the only way you'll learn it is to do some on your own so that at test time, you can do it yourself...
I'll start your homework....you finish....

the essential idea is to complete the square for each variable
first reorder the terms
x^2 - 2x +____ - 9y^2 - 18y + ___ = 9
factor out where possible
x^2 - 2x + ___ - 9 (y^2 + 2y + ___) = 9
complete the sq for both terms
in case you were wondering why I put a "space" for the constant term in the working
x^2 - 2x + 1 - 9(y^2 +2y + 1) = 9 + 1 + (-9)
factor
(x - 1)^2 - 9(y+1)^2 = 1

OK?????
you take it from here...it's almost in standard form

Answer 2

I dont know