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when the point (4,7) is on the graph of y=x^2+c

2006-11-16 16:58:03 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

put y = 7 and x =4 and solve for c
we get 7 = 16+c or c = -9

2006-11-16 17:07:58 · answer #1 · answered by Mein Hoon Na 7 · 0 0

substitute the value (4,7) to the equation, so it should be:
7=4^2+c
7=16+c
c=7-16
c=-9 (solved)

hope this helps

2006-11-17 02:50:33 · answer #2 · answered by fii 3 · 0 0

y=x^2+c
replace y and x with this value >(4,7)
(7)=(4)^2+c
7=16+c
c= -16+7
c= -9
The answer for c is -9

2006-11-17 01:12:57 · answer #3 · answered by jay17manutd 2 · 1 0

x=4
y=7
therefore,
7=4^2+c
7=16+c
-9=c

2006-11-17 01:04:45 · answer #4 · answered by Anonymous · 1 0

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