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Suppose
x^(n) = a^(m)-b^(m)
where n=/=m (if n=m then it is FLT) & m>2 & "m" is not a multiple of 2.
if these are the conditions then the above equation doesn't hold for natural solutions of "x" , "a" & "b".
Is this marvellous truth provable?

2006-11-16 16:17:42 · 3 answers · asked by rajesh bhowmick 2 in Science & Mathematics Mathematics

In this equation n>1.

2006-11-16 16:36:00 · update #1

3 answers

it's hard man

2006-11-16 16:46:51 · answer #1 · answered by fulaien 2 · 0 0

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2016-12-17 11:30:33 · answer #2 · answered by ? 4 · 0 0

it's actually x^n = a^m + b^m, not -
interesting question, i "smell" there are solutions( even if you restrict the conditions as you do),
but i have no knowledge of this solutions( if they exist)

2006-11-16 17:30:43 · answer #3 · answered by Theta40 7 · 0 0

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