2006-11-16 16:09:29 · 6 answers · asked by digz 2 in Science & Mathematics ➔ Mathematics
log4+xlogb=xloga
x(loga-logb)=log4
x=log4/(loga-logb)
2006-11-16 16:33:50 · answer #1 · answered by raj 7 · 0⤊ 0⤋
4(b)^ x = a^x
if4b = a = 0 then x can be any thing
or4(b/a)^ x = 1
so x = log base b/a of 1/4
2006-11-17 00:18:10 · answer #2 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
(a/b)^x = 4
xlog(a/b) = log4
x = log4/log(a/b) = log4/(loga-logb)
2006-11-17 01:25:46 · answer #3 · answered by Shuka 1 · 0⤊ 0⤋
4(b^x) = a^x
a^x / b^x = 4
(a/b)^x = 4
x= log_(a/b) 4
2006-11-17 00:16:47 · answer #4 · answered by can_t_get_enough 2 · 0⤊ 1⤋
4(b)^x = a^x
(a/b)^x = 4
xlog(a/b) = log(4)
x = (log(4))/log(a/b)
2006-11-17 00:24:52 · answer #5 · answered by Helmut 7 · 0⤊ 1⤋
x=(log4)/(loga - logb)
2006-11-17 00:40:18 · answer #6 · answered by rajesh bhowmick 2 · 0⤊ 0⤋