Density=Mass/volume, Therefore heating a gas increases its volume. This change has to be compromised by either mass or density. Mass cannot vary as it's a constant, so the density has to give way. Hence the change in density. When volume increases, density decreases as they are inversely proportional.
2006-11-16 17:00:40
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answer #1
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answered by SGK 2
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The density will decrease by an increase in temperature
2006-11-16 15:50:09
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answer #2
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answered by Anonymous
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when temperature increases... the air molecules gain in energy and will tend to be futher apart from each other... this leads to an increase in volume... since the there is no change in mass of gas... and thus the density of the gas should decrease... assuming that the pressure is constant...
2006-11-16 15:42:25
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answer #3
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answered by Anonymous
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The density will decrease because the gas will expand
2006-11-16 15:39:40
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answer #4
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answered by bflute13 4
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nicely you've the equation V1P1/T1 = V2P2/T2 the quantity continues to be consistent. So for both aspects of the equation to be equivalent (it fairly is V is consistent, and P2 > P1) T2 would even could extend. once you warmth up a gas the debris get excited and commence to bypass round extra causing the rigidity to develop because the quantity could proceed to be consistent.
2016-11-24 23:51:05
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answer #5
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answered by ferraro 3
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They share an inverse relationship
(ie temp up, density down) assuming that volume can vary.
2006-11-16 15:41:02
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answer #6
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answered by Scooter_MacGyver 3
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P*V = N*R*T
2006-11-16 15:57:57
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answer #7
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answered by arbiter007 6
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