k these may seem simple but i just don't remember how do these y^2-7 z^2-36??????

Question

ok i ment (y^2-7) 1st prob

(z^2-36) 2nd prob

Answer 1

These problems look as though they need factoring.
They are the difference between two squares.

Definition : a^2 - b^2 = (a - b)(a + b)
Multiply out the right-hand side to see that this is true.
So you just take the square root of each term.

y^2 - 7 = y^2 - [sqrt(7)]^2 = [ y - sqrt(7) ] [ y + sqrt(7) ]

z^2 - 36 = z^2 - 6^2 = (z - 6)(z + 6)

Answer 2

clarify; do you mean;
(y^2)-(7z^2)-36