What is the relationship between the lenght of a pendulum and its period (e.g. how wil the period of the pendulum change-proportionality- if you change the lenght from .1m to .2m)
What is the relationship between mass and period...if any
What is the relationship between the angle of release for the pendulum and the period
I would really appreciate if you could help me in anu of these
2006-11-16 14:03:23 · 4 answers · asked by Sir Excalibur 2 in Education & Reference ➔ Homework Help
ok so are they proportinal to each other, or the square of one, of the square root?
2006-11-16 14:10:22 · update #1
ok ty now i only need to now through what proportion are the length and period related??
2006-11-16 14:14:19 · update #2
T=2*PI*sqrt(l/g)
T_.2/T_.1 = sqrt(0.2/0.1)
so the ratio will be sqrt of 2 which is 1.414
This means that Time period of pendulum will increase if we increase the length of the string.
Angle of release should be very small.
as you know we are approximation the curve of the motion of simple pendulum as a straight line. Lim Theta->0, sintheta/theta->1. Not valid for larger angles.
Hope this helps
2006-11-16 14:20:27 · answer #1 · answered by rendezvous247 1 · 0⤊ 0⤋
the longer the lenght of the string the longer it takes to complete an oscillation the mass has no effect on the time of a oscillation
2006-11-16 14:08:22 · answer #2 · answered by bell 4 · 0⤊ 0⤋
Philip's answer is correct To answer one of your other questions, the period is also independent of the release angle
2016-03-17 07:24:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋
angle of release has no effect either.
period is proportional to the (see below)
(look under basic principles.)
2006-11-16 14:16:29 · answer #4 · answered by Eric 2 · 0⤊ 0⤋