How do you solve for x?

Question

a) x^2+5xy+4y^2=0
b)2x^2-5xy-3y^2=0
c)4x^2-4xy+y^2=0
d) 2x^2/5 + 7xy/10 - y^2/5=0
e)5x^2+xy=0
f)3x^2-7xy=0

thxx plz show work!

Answer 1

a) (x+4y)(x+y)=0 x=-y or -4y

b) (2x+y)(x-3y)=0 x=-y/2 or 37

c) (2x-y)(2x-y)=0 x=y/2

d) 4x^2+7xy-2y^2=0
(4x-y)(x+2y)=0 x=y/4 or -2y

e) x(5x+y)=0 x=0 or -y/5

f) x(3x-7y)=0 x=0 or 7y/3

Answer 2

I'll do the FIRST one:

a) you know its a product of factors in x and y:

(x y)(x y)

Since all the coefficients are positive, both are "+"

(x + y)(x + y)

Since the leading term is x^2, you are done with the x's.

Now, find two numbers who product is 4 and whose sum is 5:

1 and 4:

(x + 4y)(x + y)

Check your work by using FOIL to multiply it back out to the original question.