2006-11-16 12:10:59 · 4 answers · asked by jrosales9@sbcglobal.net 1 in Science & Mathematics ➔ Mathematics
Uh, probably nothin'. Did you mean 9x^4 + 6x^2 + 1?
2006-11-16 12:16:07 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The square root of 9x ^ 4 + 4 x^ 2 + 1 doesn't exist !
But the square root of 9x ^4 + 12x ^2 + 4 exist and the answer is
( 3x ^2 + 2)
verification : (3x ^2 + 2 ) (3x ^2 + 2)
= 9x ^4 + 6 x ^2 + 6 x ^2 + 4
= 9x ^4 + 12x ^2 + 4
2006-11-16 20:33:10 · answer #2 · answered by frank 7 · 0⤊ 0⤋
if you mean (9x^4+6x^2+1) then square root is (3x^2+1)
other wise above is not a perferct square
2006-11-16 20:32:05 · answer #3 · answered by Mein Hoon Na 7 · 0⤊ 0⤋
did anyone else do this problem three times wondering what they were doing wrong. 6x^2!!!!!
2006-11-16 20:35:52 · answer #4 · answered by xian gaon 2 · 0⤊ 0⤋