can you help solve this and show work please
8(w+4)=w^3+2w^2-8w
thanks
2006-11-16 12:02:09 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
8(w+4)=w^3+2w^2-8w
<=> w^3 + 2w^2 -16w - 32 = 0
<=> w^2(w+2) -16(w+2) = 0
<=> (w^2 - 16)*(w+2) = 0
<=> (w-4)*(w+4)*(w+2) = 0
2006-11-16 12:16:57 · answer #1 · answered by James Chan 4 · 0⤊ 0⤋
i can help with the first half use the distributive property and u get 8w+32=w+-8w so what u can do is subtract w from both sides and you'll get this:7w+32=-8w then u can subtract7w from both sidesand get this: 32= -15w then divide both sides by -15 to get w by itself and once u do that ur awnser should be -2.13=w the whole process is a basic repeatetive step of inverse operations.
2006-11-16 20:24:40 · answer #2 · answered by i love dogs 1 · 0⤊ 0⤋
w^3+2w^2-16w-32=0
(w+2)(w^2-16) =0
(w+2)(w-4)(w+4) =0
2006-11-16 20:07:35 · answer #3 · answered by paladin 1 · 1⤊ 0⤋
sorry do,nt know
2006-11-16 20:04:16 · answer #4 · answered by plinko's mom 2 · 0⤊ 1⤋