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8x^4 + x^2 + 9 / x^4

***8x^4 + x^2 + 9 all divided by x^4****

Am I doing this right?

8x^4/x^4 + x^2/x^4 + 9/x^4
Is the answer............. 8x + x^-2 + 9x^4 ??????

2006-11-16 11:47:51 · 3 answers · asked by C.H. 1 in Science & Mathematics Mathematics

FOR ANOTHER PROBLEM:
-4x + 12/ -4x ***-4x + 12 all over -4x**

First I........... -4x/-4x + 12/-4x and got x - 3x
IS THIS CORRECT?

2006-11-16 11:56:48 · update #1

3 answers

You left out the negative sign in front of the 4 on the last term and the x^4 cancels in the first term
Answer: 8 + x^-2 + 9x^-4 or you could write it like this
8 + 1/x^2 + 9/x^4

2006-11-16 11:50:41 · answer #1 · answered by MsMath 7 · 5 5

no , but almost
8 x^4 + 9 / x^4 = 8 ( x*4 + x^2) =9 = 8 x^6 + 9 / x^4 =

8 ( x^6 - 4 ) + 9 = 8x^2 + 9 you were almodt right the only thimg you did not do is drop the *^4 in the dpminatir

2006-11-16 19:59:16 · answer #2 · answered by Anonymous · 4 1

(8x^4 + x^2 + 9) / x^4
let's say
a = x^2
(8a^2 + a + 9)/ a^2
factor the numerator
the numerator cannot be factored
try the quadratic formula
if the number inside the radical is negative, then it cannot be factored

2006-11-16 19:53:13 · answer #3 · answered by trackstarr59 3 · 3 1

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