A mass of 1kg is on a frictionless table connected to a string over a pulley to a .5kg mass suspended over the edge of a table. What is the acceleration of each mass??
At first, I got 9.8m/s^2 for both of them...but it seemed wrong. Any ideas?
2006-11-16 11:33:09 · 2 answers · asked by bep 2 in Science & Mathematics ➔ Physics
The only force comes from the hanging mass, its weight,
F = W = .5kg*9.8m/s^2.
The mass to be accelerated totals 1.5kg, so
a = F/1.5kg = (.5kg*9.8m/s^2)/1.5kg = (1/3)*9.8m/s^2
2006-11-16 11:53:15 · answer #1 · answered by sojsail 7 · 0⤊ 0⤋
Just think about the mass on the table. It has a force pulling on it equal to (.5kg)(9.81m/s2). Or, 4.9N
To fing its acceleration: a= F/m 4.9N/1kg = 4.9 m/s2
The other mass has the same acceleration.
2006-11-16 11:56:10 · answer #2 · answered by Alan J 3 · 0⤊ 0⤋