If y(x-1)=z then x=
can someone explain this to me so it makes sense (not just the answer)
2006-11-16 11:00:12 · 5 answers · asked by Belinda M 1 in Science & Mathematics ➔ Mathematics
y(x-1) = z
Distribute the y
yx - y = z
Add y to each side
yx = z + y
Divide both sides by y
x = (z+y)/y
2006-11-16 11:03:55 · answer #1 · answered by MsMath 7 · 4⤊ 3⤋
hi x=(z/y)+1
2006-11-16 19:09:39 · answer #2 · answered by mane 5 · 2⤊ 0⤋
y(x-1)=z <--- Distributive Property
yx-y=z
yx-y+y=z+y <--- Add y to each side
(yx)/y = (z+y)/y <--- Divide both sides by y
x= (z+y)/y <---- Simplify
x= (z/y) +1
2006-11-16 20:41:13 · answer #3 · answered by Jasmine 5 · 2⤊ 0⤋
Distrubute and solve for x:
(x(y) - 1(y) = z
xy - y = z
Now we want to isolate x:
xy = z + y
x = (z + y)/y
Voila! Hope this helps :)
2006-11-16 19:04:14 · answer #4 · answered by disposable_hero_too 6 · 3⤊ 0⤋
yx-y=z
yx=z+y
x=(z+y)/y
2006-11-16 19:03:57 · answer #5 · answered by 7 · 4⤊ 0⤋