how do u do this
2006-11-16 10:58:07 · 6 answers · asked by tammy g 1 in Science & Mathematics ➔ Mathematics
I think you missed the ^2 on your quadratic equation
15x^2-8x-16
=15x^2 -20x +12x -16
=5x(3x-4) +4(3x-4)
=(3x-4)(5x+4)
2006-11-16 11:01:27 · answer #1 · answered by Fahd Shariff 3 · 2⤊ 0⤋
15x^2 - 8x - 16
my teacher uses this thing called the "cow"
take the 15 and multiply it to the -16
x^2 - 8x - 240
(x + ?)(x - ?)
(x + 12)(x - 20)
divide the 15 back out of the the factored problem
it doesnt necessarily have to be 15, it can be factors of 15
(3x - 4)(5x + 4)
check it
ANSWER
(3x - 4)(5x + 4)
2006-11-16 19:29:55 · answer #2 · answered by trackstarr59 3 · 0⤊ 0⤋
Are you sure you have the formula correctly?
If you really meant 15x - 8x - 16, then
an only thing you can do is to take X outside and make it:
x(15 - 8) - 16
simply this and get:
7x - 16
2006-11-16 19:05:20 · answer #3 · answered by tkquestion 7 · 0⤊ 1⤋
Is this correct or is the first term squared?
assuming the equation is correct:
7x - 16 = 0
7x = 16
x = 16/7
assuming the first term is squared
(5x +4)(3x - 4)
you need numbers so that the out side and inside term add
to -8 and the last two terms multiply to -16
2006-11-16 19:05:56 · answer #4 · answered by ve1luv 2 · 0⤊ 1⤋
15^2 -8x -16
find 15*16 which is 240
then find sum of 240 that will give you -8
which is -20 and 12
15^2 -20x + 12x - 16
(15^2 - 20x) (12x- 16)
5x(3x-4) 4(3x-4)
anwser is (5x+4)(3x-4)
2006-11-16 21:04:45 · answer #5 · answered by Angel Girl 5 · 0⤊ 0⤋
x(15-8-16)
2006-11-16 19:02:52 · answer #6 · answered by Anonymous · 0⤊ 2⤋