If you add 125 grams of C2H6O to your gas, how many grams of CO2 and H2O can be produced?

Answer 1

Take the 125g ethanol (E), C2H6O, and multiply by 1 molE/46gE.
The gE cancel, leaving moles E. For the CO2 part, multiply by 2 mol CO2/1 molE. That comes from the balanced equation. The molE cancel, leaving molCO2. Next multiply by 44gCO2/1mol CO2. The molCO2 cancel, leaving gCO2. That's the first part of the problem. Next, go back to the beginning where you got molE. Multiply by 3molH2O/1molE. This also comes from the balanced equation.The molE cancel, leaving molH2O. Multiply by 18gH2O/1molH2O. The molH2O cancel, leaving the gH2O, which is the second part of the problem. At. wts. C=12, H=1, O=16, C2H6O=46

Answer 2

Wow alot of questions with the help of you. properly for this question we first could desire to artwork out the mols of C2H6O. style of mols = Mass / Molar Mass style of mols = 126 / (12 x 2 + a million x 6 + sixteen) = 2.74mols because of the fact the mol ratio of C2H6O and H2O are a million:a million mol ratio So the burden of H2O is 1mol Mass = style of mols x Molar Mass Mass = 2.seventy 4 x (a million x 2 + sixteen) = forty 9.5g EDIT: Crap z4zorro is stable, i did no longer stability the equation, so his answer is probable precise.