(3t^4)(9t^0)??

11 ⤊

ugh i hate math...
I know it would be something like 27t, but what would be the exponent for t?

2006-11-16 10:35:16 · 3 answers · asked by makelovenothate 2 in Science & Mathematics ➔ Mathematics

thanks a bunch

2006-11-16 13:12:09 · update #1

3 answers

(3t^4)(9t^0)
t^0 is just 1.
= (3t^4)(9)
= 27t^4

2006-11-16 10:37:09 · answer #1 · answered by MsMath 7 · 4⤊ 4⤋

t^0 = 1

3t^4*9 = 27t^4 = t(3t)^3

2006-11-16 18:39:49 · answer #2 · answered by disposable_hero_too 6 · 4⤊ 0⤋

Anytime you're multiplying a variable against itself, but raised to whatever power, just add the exponents:
(Cx^a)(Dx^b)=CDx^(a+b)

And if you divide, you subtract:
(Cx^a)/(Dx^b)=C/Dx^(a-b)

2006-11-16 18:47:56 · answer #3 · answered by retfordt 2 · 3⤊ 0⤋