What is the step by step method of finding this...
"find the hypotenuse of the right triangle that has a base of 12 and a side leg of 20"?
2006-11-16 10:29:32 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Where c is the hypotenuse, and a and b are legs of the triangle:
c² = a² + b² --- Pythagoren Therom
c² = (12)² + (20)² --- Replace what you know...
c² = 144 + 400 --- Find 12² and 20²...
c² = 544 --- Add them together...
c = √544 --- Square root of 544 equals c
c ≈ 23.32"
2006-11-16 10:31:02 · answer #1 · answered by Anonymous · 1⤊ 0⤋
the hypotenuse would be represented as H so:
H^2= 12^2+20^2
2006-11-16 11:35:07 · answer #2 · answered by Guido F 2 · 0⤊ 0⤋
Pythagorean Theorem: a^2 + b^2 = c^2 where c = hypotenuse and a and b are the sides in a right triangle.
So:
12^2 + 20^2 = c^2
144 + 400 = c^2
c^2 = 544
c = sqrt(544) = 23.324
Hope this helps!
2006-11-16 10:31:29 · answer #3 · answered by disposable_hero_too 6 · 0⤊ 0⤋
the hypotenuse is the longest side of the triangle so the hypotenuse is 20
2006-11-16 10:39:03 · answer #4 · answered by Brendan 2 · 0⤊ 0⤋
Repeat after me -
The square of the hypotenuse is equal to the sum of the squares on the other two sides.
2006-11-16 10:31:59 · answer #5 · answered by Anonymous · 0⤊ 0⤋
A squared + B squared = C squared
C squared = the hypotenuse
12 squared + 20 squared = C squared
144 + 400 = C squared
544 = C squared
You do the rest.
2006-11-16 10:34:57 · answer #6 · answered by ♥☺ bratiskim∞! ☺♥ 6 · 0⤊ 0⤋
(12^2+20^2)^.5
2006-11-16 10:32:30 · answer #7 · answered by Arnaud B 1 · 0⤊ 0⤋