A constant force of 100N is applied to a mass of 40.0kg. The force causes a displacement of 20.0m to this mass along the positive x axis. Neglect friction. What is the work done by the component of the force along the positive x axis. By the way, the force is coming from and angle of 40 degrees.
Can you please show me how to do this. Thanks.
2006-11-16 09:31:43 · 2 answers · asked by bluevolleyball12 1 in Science & Mathematics ➔ Physics
To Hung N: I'm trying to do my homework, but it's multiple choice and I can't get the right answer, so I called other people and they don't know, so now I'm asking others. The least you could do is help...
2006-11-16 09:56:27 · update #1
Thanks Pascal, but thats what I did, but my teacher says the ansewr is 1520Nm, is 1520Nm possible?
2006-11-16 10:31:10 · update #2
The work done on an object by a force is the product of the component of the force in the direction of motion and the distance the object moves. The component of the force in the x direction is simply the magnitude of the force times the cosine of the angle. Thus:
W = 100 N * cos 40° * 20.0 m ≈ 1530 J (to 3 significant digits)
Edit: I don't know whether your teacher is complaining about the units or the numbers. A joule IS a newton·meter, so both units are correct. As for the number, I'd say someone made a typo when compiling the answer key. It happens a lot. Ask her to recompute it herself.
2006-11-16 10:12:06 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
Do your own homework!!!
2006-11-16 09:33:49 · answer #2 · answered by Hung N 2 · 0⤊ 0⤋