2006-11-16 09:24:34 · 5 answers · asked by kayla y 1 in Science & Mathematics ➔ Mathematics
Factor the numerator.
n^3 - 27 is a difference of cubes.
n^3 - 27
= n^3 - 3^3
= (n-3)(n^2 + 3n + 9)
You can cancel the (n-3)'s leaving you with
n^2 + 3n + 9
2006-11-16 09:25:56 · answer #1 · answered by MsMath 7 · 4⤊ 3⤋
n^3 - 27 / n-3
factoring: (n-3)(n^2 + 3n + 9) / (n-3)
then: n^2 + 3n + 9
2006-11-16 09:37:41 · answer #2 · answered by Doug R 5 · 3⤊ 0⤋
do synthetic division
we get n^2 +3n+9
i cant show synthetic division here
check it here
it is easiest method
http://en.wikipedia.org/wiki/Synthetic_division
2006-11-16 09:29:15 · answer #3 · answered by . 3 · 5⤊ 0⤋
n^3-27/n-3
(n-3)(n-3)(n-3)/(n-3)
Cancel one (n-3) from below and above
now remanes (n-3)(n-3)
which equals to
n^2-6n+9
2006-11-16 09:28:50 · answer #4 · answered by Kewl guy 3 · 3⤊ 3⤋
yeh do the difference of cubes.
2006-11-16 09:31:52 · answer #5 · answered by drizzttownz 2 · 2⤊ 0⤋