y=sin pi/2x+1 find x intercepts?

Question

it gives a graph but idk how to do it

Answer 1

The x-intercepts are where y is zero, hence, crossing the x-axis.
y = sin(pi/2x) + 1
Set y = 0
then, sin(pi/2x) = -1
So what value of x will make sin()=-1
Well, when the argument pi/2x is some multiple of pi/2, like 3pi/2, 7pi/2, into + then - infinity. Let's see, we want 3, 7, 11,... on the positive side and -3, -7, -11,... on the negative side. Thinking about it yields an odd number plus 4; an odd number is 2n+1, then adding 4, 2n + 5. Let's try it: for n=-1, 2n+5=3; for n=0, 2n+5=5; for n=1, 2n+5=7; and the same for the negative side.
Back to the original argument of sine:
pi/2x = 2n+5 for n = -infinity to + infinity
(2n+5)2x = pi
x=pi/[2(2n+5)] for n =

Answer 2

x intercepts occur when y = zero
so your equation will be as follows:
sin pi/2x + 1 = 0
solve for x

Answer 3

Put the equation in the graphing calculator:
y=sinπ/2x+1

That will show you where the x-intercepts are.

Answer 4

if u have a ti-83 or higher, u go on the graph screen and then choose math, then u select zeros, then u choose a point on the top of the graph, then a point on the bottom. (any point will do)

Answer 5

is it sin (pi/2x+1) or sin (pi) (2x +1) or sin (pi)2x + 1 or sin (pi * 2x) + 1?