(a-1/a+1)+(a+1)(a-1)?

Answer 1

a^3+a^2-2

Answer 2

Multiply the first one by (a-1/a-1) and the second by (a+1/a-1) and you get (a-1*a-1)/(a+1*a-1) + (a+1*a+1)/(a+1*a-1). That simplifies to ((a+1)^2 + (a-1)^2)/(a+1*a-1). Multiply out the parentheses: (a^2 + 2a + 1 + a^2 -2a +1)/(a^2 -1). Now you can simplify that to (2a^2 + 2)/(a^2 - 1). I bet it can be simplifed further but I don't know how right off the top of my head.

Hope that's at least a good start.

Answer 3

jozallen, you are a moron.

Actually there isn't a question here. We can't solve for a because the question doesn't say what the equation equals.

We can certainly rearrange the equation in an infinite number of ways but that is rather a meaningless exercise.

Needless to say the equation can't be reduced to 2a.

It can be put over a common denominator:

(a^3 + a^2 - 2)/(a + 1)

sumi had it right but the way the answer was written needs parens to get the order of operations correct.

Answer 4

if this is a math question the answer is 2a
here is proof:
let's combine like terms and simplify this so you get this
a-1
------ +a+1(a-1)
a+1

alright the a-1 and a+1 cancel each other out so you get

a+1(a-1)
multiply 1 times everything in parentasees.

a+1+a-1
combine like terms
2a
the +1 and -1 cancel each other out so you're left with 2a.

Answer 5

(a-1/a+1) cannot be simplified. but the other part can be simplified:

a^2 - 1

Answer 6

multiply the first fraction by (a-1)/(a-1) and the second by (a+1)/(a+1). this is called multiplying by the conjugate. see if you can get it from there. good luck!

Answer 7

taking lcm
a-1+(a+1)^2(a-1) /a+1
a-1+(a+1)(a^2-1)/a+1
a-1+a^3-a+a^2-1/a+1
a^3+a^2 -2/a+1

Answer 8

Click on the link below for the work-out answer problem.

http://www.fbixtreme.com/David/yah%201.jpg

Answer 9

(edit)
Actually my answers wrong